costdsint等于多少
帮忙计算这两个积分。图看的清楚吧 -
你好1、∫costdsint =∫cos² tdt =∫(1+cos2 t)2dt =1/2t+sin2t/4+C 2、令x=sint,则t=arcsint,dx=costdt,
∫costdsint =∫cos²tdt =∫(cos2t+1)2dt =1/4∫cos2td(2t)1/2∫dt =1/4sin2t+1/2t +C 满意请采纳,谢谢!
你好1、∫costdsint =∫cos² tdt =∫(1+cos2 t)2dt =1/2t+sin2t/4+C 2、令x=sint,则t=arcsint,dx=costdt,
∫costdsint =∫cos²tdt =∫(cos2t+1)2dt =1/4∫cos2td(2t)1/2∫dt =1/4sin2t+1/2t +C 满意请采纳,谢谢!
∫√(1-x²)dx =∫costdsint =∫cos²tdt =tcos²t+∫sin2tdt =tcos²t-cos2t/2+c =t-tsin²t+sin²t-1/2+c =(1-x²)arcsinx+x²+c'
=-∫[(sint)^2+(cost)^2]dt =-t+C C是常数,
sin2t的不定积分是多少? -
sin^2t的不定积分等于t/2-1/4*sin2t+C。解:∫sin^2tdt =∫(1-cos2t)/2dt =∫1/2dt-1/2∫cos2tdt =1/2*t-1/4∫cos2td2t =t/2-1/4*sin2t+C
此结果是x²在积分号的上面,0在下面的结果若相反,请加负号Φ(x)(#643;2 x^2)e^tcostdt =(#643;2 x^2)e^tdsint =e^t*sint(x^2,0)-(#643;2 x^2)e^t*sintdt =e^t*sint(x^2,0)+(#643;2 x^2)e^tdcost =e^t*sint(x^2,0)+e^t*cost(x^等会说。
costdsint在0到π/2的积分等于 -
答,
=∫-(sint)^2dt-(cost)^2dt =-∫[(sint)^2+(cost)^2]dt =-t+C C是常数,
∫3tcostdt等于多少 -
∫3tcostdt=∫3tdsint=3tsint-3∫sintdt=3tsint+3∫dcost=3tsint+3cost+c