costdsint等于什么
一道数分题,求教,谢谢! -
令sint = x t属于(pai/3 ,pai/3)∫(sint)#179;[1-(sint)#178;]^(1/3)dsint =∫(sint)#179;costdsint =∫(sint) ³ (cost)² dt =∫(cost)²(1-cost²)sint dt =∫(cost)²[(cost)^2 - 1)] dcost ╮(╯▽╰)╭,那时候的题都有帮助请点赞。
∫costdsint =∫cos²tdt =∫(cos2t+1)2dt =1/4∫cos2td(2t)1/2∫dt =1/4sin2t+1/2t +C 满意请采纳,谢谢!
令sint = x t属于(pai/3 ,pai/3)∫(sint)#179;[1-(sint)#178;]^(1/3)dsint =∫(sint)#179;costdsint =∫(sint) ³ (cost)² dt =∫(cost)²(1-cost²)sint dt =∫(cost)²[(cost)^2 - 1)] dcost ╮(╯▽╰)╭,那时候的题都有帮助请点赞。
∫costdsint =∫cos²tdt =∫(cos2t+1)2dt =1/4∫cos2td(2t)1/2∫dt =1/4sin2t+1/2t +C 满意请采纳,谢谢!
x=sint,t∈[-π/2,π/2]∫√(1-x²)dx =∫costdsint =∫cos²tdt =tcos²t+∫sin2tdt =tcos²t-cos2t/2+c =t-tsin²t+sin²t-1/2+c =(1-x²)arcsinx+x²+c'
=∫-(sint)^2dt-(cost)^2dt =-∫[(sint)^2+(cost)^2]dt =-t+C C是常数,
帮忙计算这两个积分。图看的清楚吧 -
你好1、∫costdsint =∫cos² tdt =∫(1+cos2 t)2dt =1/2t+sin2t/4+C 2、令x=sint,则t=arcsint,dx=costdt,
答,
∫sintdcost-costdsint=? -
=∫-(sint)^2dt-(cost)^2dt =-∫[(sint)^2+(cost)^2]dt =-t+C C是常数,