2772÷28+34965÷35=(
2772÷28+34965÷35=? -
=99+999 =1098
(1)2772÷28+34965÷35,99+999,99+1000-1,1099-1,1098;(2)8795-4998+2994-3002-2008,(8795+2994)(4998+3002)2008,11789-8000-2008,3789-2008,1781;故答案为:1098,1781.
=99+999 =1098
(1)2772÷28+34965÷35,99+999,99+1000-1,1099-1,1098;(2)8795-4998+2994-3002-2008,(8795+2994)(4998+3002)2008,11789-8000-2008,3789-2008,1781;故答案为:1098,1781.
2772/28+34965/35 =(2800-28)/28+(35000-35)/35 =100-1+1000-1 =1098
2772/28+34965/35 =(2800-28)28+(35000-35)35 =100-1+1000-1 =1100-2 =1098
2722除以28加上34965除以35的和如何巧算 -
2722除以28加上34965除以35 应该为2772 2772/28+34965/35 =(2800-28)/28+(35000-35)/35 =100-1+1000-1 =1100-2=1098
1098
395-283+154+246-117. 2772÷28+34965÷35. 8795-4998+2994-3002-20...
154+246)-(283+117),795-400,395;(2)2772÷28+34965÷35,99-999,-900;(3)8795-4998+2994-3002-2008,(8795+2994)(4998+3002+2008),11789-10008,1781;(4)125×198÷(18÷8),125×198÷18×8,(125×8)×(198÷18),1000×11,11000.
解:2772/28+34965/35 =[(2772+28)/28-1]+[(34965+35)/35-1]=[2800/28-1]+[35000/35-1]=[100-1]+[1000-1]=100+1000-1-1 =1100-2 =1098 2. 1999+1998-1997-1996+1995+1994-19 93-1992+还有呢?+7+6-5-4+3+2-1 =(1999+1998-1997-1996)+(1995+1994-1993-1992)+还有呢?+(还有呢?
用简便算法计算 -
2772÷28+349653÷5 =(2800-28)÷28+(35000-35)÷35 =100-1+1000-1 =1100-2 =1098
(5738-760)/19=(5700+38-760)/19=5700/19+38/19-760/19=300+2-40=262 2772/28+34965/35=(2800-28)/28+(35000-35)/35=100-1+1000-1=1098